6w^2+16w-80=0

Solution for 6w^2+16w-80=0 equation:

6w^2+16w-80=0

a = 6; b = 16; c = -80;
Δ = b2-4ac
Δ = 162-4·6·(-80)
Δ = 2176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2176}=\sqrt{64*34}=\sqrt{64}*\sqrt{34}=8\sqrt{34}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8\sqrt{34}}{2*6}=\frac{-16-8\sqrt{34}}{12}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8\sqrt{34}}{2*6}=\frac{-16+8\sqrt{34}}{12}
$